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Implicit typecasting
The compound operators (+=, -=, *=, and /=) do implicit typecastiong. If you compile the following code you will get a compilation error that 'possible loss of precision'.
byte a = 9;
a = a + 5;
Although the result wil fit to byte this operation produces int value.
But when we use compound operator a += 5; compiler will be happy because compound operators make implicit typecast.
Hence this shorthand is equal to
a = (byte) (a + 5);
Author: Jafar N.Aliyev (Jsoft)
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