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Implicit typecasting

The compound operators (+=, -=, *=, and /=) do implicit typecastiong. If you compile the following code you will get a compilation error that 'possible loss of precision'.

byte a = 9;
a = a + 5;

Although the result wil fit to byte this operation produces int value. But when we use compound operator a += 5; compiler will be happy because compound operators make implicit typecast. Hence this shorthand is equal to

a = (byte) (a + 5);

Author: Jafar N.Aliyev (Jsoft)

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